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x^2+40=8
We move all terms to the left:
x^2+40-(8)=0
We add all the numbers together, and all the variables
x^2+32=0
a = 1; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·1·32
Δ = -128
Delta is less than zero, so there is no solution for the equation
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